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Answers (1)

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Sol. Here, we have a room surrounded by a varandha

We have given,
Area of room =5 x 4
=20m2
Area of square =22m2
Therefore Area of entire ABCD=(20+22)
(5+2x)(4+2x) =42
20+10x+8x+9x2 =42
4x2 +18x+20=42
2x2 +9x+10=21
2x2+9x-11=0
2x2 +112-2x-11=0
x(2x+11)-1(22 +1)=0
(2x+11)(x-1) =0
x=-11/2 , x=11
Hence, the width of the varandha is1.