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example 17: I got the amount to be removed as 5/6th of the solution. This is how i approached:
1: let x solution be removed and x syrup be added, so 2x/5 syrup removed and 3x/5 water removed. 2:syrup in solution after removal=2-2x/5 3:water in solution after removal=3-3x/5. 4:to this solution we add x parts syrup so syrup in solution becomes 2-2x/5 x while water in solution remains the same. 5: as per the condition after the above process we have 2-2x/5 x=3-3x/5 or x=5/6. there amount removed was 5/6th of solution.------------pls help me understand this.
ALSO I HAVE POSTED FEW MORE QUESTION, PLS HELP ME BY REPLYING TO THEM. thanks in advance!
Answers (1)
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Dear student! your approach is perfectly alright. You got x = 5/6 , which is also correct. But you took the initial quantity of mixture to be 5 . So 5/6 is 1/6th part of 5 . Even if you take the initial qty of mixture to be 100 liters, then again you will get the same fraction . So irrespective of the initial qty , one would get the fraction to be 1/6th of initial qty.