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  • not abe to understand how do we calculste votes to be 200/(2/3) in the first question of percentage. Please explain.
    Asked by  11 months ago
     
 
 

Answers (2)

 
  • By , 11 months ago
    Initially number of voters = 800

    Let initially number of voters (for) = x

          Initially number of voters(against) =y

      x + y = 800

    Now 

    1/3 of for voters are abducted , also the strength of against voters increase by 100% i.e. they become double

     For                                Against

    2x/3 - y                               2y



      given 2y =  50% of (initial)

                     = 1/2 . 800 = 400

     y = 200 and so x = 600

    Now for voters = 2x/3 - y  = 2/3 . 600 - 200 = 200

     2y = 2 x 200 = 400

     So now voters (for) = 200

                   Voters (against) = 400
 
  • By , 11 months ago
    tan7A-tan5A-tan2A=tan7A.tan5A.tan2A
 
 
 
 

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