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  • Q-A stone is projected from the top of a tower. When it crosses a point 5m below the top, another stone is let fall from a point 25m below the top. Both stones reach the bottom of the tower simultaneously. Find the height of the tower .

    Asked by  2 years ago
     
 
 

Answers (1)

 
  • By , 2 years ago
    let height be h
    Time taken to reach the bottom = (2(h-25)/g)1/2
    so h-5 = u* (2(h-25)/g)1/2 + g (2(h-25)/g) /2
    => 20 = u* (2(h-25)/g)1/2
    => 400 = 2*10*5 (2(h-25)/10)     [as u2 = 2gs]
    => 4 = (h-25)/5
    so h = 45m
 
 
 
 

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