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  • sir plz help me with dis numerical'A particle is moving along a circular path with constant speed v.What is the change in velocity when the particle completes one fourth of a revolution?
    Asked by Clarke1678 4 months ago
     
 
 

Answers (1)

 
  • By , 4 months ago
    Since the speed is constant, clearly the change in the magnitude of velocity is constant.

    Now, consider two instants - the instant when the particle has the coordinate (0, a) and the instant when it has the coordinate (a, 0).

    The particle completes one fourth of a revolution as it moves from (0, a) to (a, 0). Here a is the radius of the circle.






    If the x axis is horizontal and the y axis is vertical, then in the first case, the velocity is vi and in the second case, the velocity is -vj.


    The difference in velocities is -vj - vi.

    You can similarly calculate the difference in velocities between any other points by finding the difference between the velocity vectors at those points.  


 
 
 
 

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