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sir plz help me with dis numerical'A particle is moving along a circular path with constant speed v.What is the change in velocity when the particle completes one fourth of a revolution?Asked by Clarke1678 4 months ago
Answers (1)

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Since the speed is constant, clearly the change in the magnitude of velocity is constant.
Now, consider two instants - the instant when the particle has the coordinate (0, a) and the instant when it has the coordinate (a, 0).
The particle completes one fourth of a revolution as it moves from (0, a) to (a, 0). Here a is the radius of the circle.
If the x axis is horizontal and the y axis is vertical, then in the first case, the velocity is vi and in the second case, the velocity is -vj.
The difference in velocities is -vj - vi.
You can similarly calculate the difference in velocities between any other points by finding the difference between the velocity vectors at those points.